![]() Then, the volume of ethanol in 0.11 mole = 58.39 ✕ 0.11 mL It means that one mole of ethanol is present in 58.39 mL. The volume of ethanol = mass of ethanol / density The molar mass of ethanol (C₂H₅OH) is 46.07 g / mol. It is given that the density of ethanol is 0.789 g / mL. ![]() The density of a substance is equivalent to the ratio of the mass and volume of the substance.ĭensity = mass of substance / volume of substance The number moles of ethanol = 1 / 2 ✕ 0.22 mol The number moles of ethanol required to produce 0.22 mol CO₂ is calculated as follows: It can be inferred that 2 mol of CO₂ is produced from 1 mol of ethanol.ġ mol of CO₂ is produced from 1/ 2 mol of ethanol. The balanced chemical equation for combustion of ethanol is :Ĭ₂H₅OH (l) + 3 O₂ (g) → 2 CO₂ + 3 H₂O (l) The number of moles of CO₂= 10.0 g / (44.01 g / mol) The molecular weight of CO₂is 44.01 g / mol. The amount of carbon dioxide (CO₂) produced is 10.0 g. The number of moles of substance = given weight / molecular weight The number of moles substance is defined as the ratio of the given weight of the substance to molecular weight of substance.
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